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Four of the carbons are equivalent.Įvaluate the spectrum for compound A based on what you already know from the UN/DBE and IR spectrum.

Which of the given statements is true? All the carbons are nonequivalent. Compare the number of signals in the spectrum and the number of carbons from the molecular formula for compound A. The systematic methods of naming alcohols follow a similar procedure and the names have three main parts: 1) specifying the information about the substituents, 2) specifying the information about the parent chain, and. The ROR group is the functional group of an ether. Although carbon signals cannot be integrated, the relative size of peaks in the carbon spectrum can help determine how many equivalent carbons are present in a single signal. The OH group is the functional group of an alcohol. If two carbons in a molecule are equivalent (such as in an isopropyl group) they only produce one signal in the spectrum. Carbon spectra say a lot about the symmetry of the molecule. alkyne aldehyde ring nitrile carboxylic acid benzene ring ether ketone OOOOOOOOO epoxide amine alcohol alkene esterĮxamine the 13C spectrum of compound A. Check all the functional groups that could be present in compound A. Now, using the IR data you should be able to narrow this list. What is this peak most likely due to? O C-H(sp) O C-H (sp) O C-H (sp) 0-H or N-H C-O or N-O C=0Įarlier, using the molecular formula and the UN/DBE, you came up with a list of functional groups that could be present in compound A. In this IR spectrum you should focus on the peak ~2900–3000. The peaks below 1500 cannot be used to make any structural assignments because they are in the fingerprint region.

The peak at ~3300 is due to residual amount of water in the sample and therefore it will not be considered. Examine the IR spectrum provided for compound A.